\[ch\left({α±ß}\right)=ch\ α·ch\ ß±sh\ α·sh\ ß\]
\[sh\left({α±ß}\right)=sh\ α·ch\ ß±ch\ α·sh\ ß\]
\[th\left({α±ß}\right)=\frac{th\ α±th\ ß}{1±th\ α·th\ ß}\]
\[cth\left({α±ß}\right)=\frac{1±cth\ α·cth\ ß}{cth\ α±cth\ ß}\]
\[\begin{array}{rccccl}
ch^2\ α-sh^2\ α = 1 & = & \left({ch\ α + sh\ α}\right) & · & \left({ch\ α - sh\ α}\right) & =\\
& {\ } &|| & {\ } &|| & {\ } \\
& = & e^α \quad & · & e^{-α} & = \displaystyle{\frac{e^α}{e^α}}=1
\end{array}\]
USEFUL AjAx LaTeX REFERENCES (to produce the above) ::
https://docs.mathjax.org/en/v2.7-latest/tex.html
https://math.meta.stackexchange.com/questions/5020/mathjax-basic-tutorial-and-quick-reference
\[ch^2\ α+sh^2\ α=ch\left({2α}\right)=2ch^2\ α-1=2sh^2\ α+1\]
\[sh\left({2α}\right)=2·sh\ α·ch\ α\]
\[th\left({2α}\right)=\frac{2·th\ α}{1+th^2\ α}\]
\[cth\left({2α}\right)=\frac{1+cth^2\ α}{2·cth\ α}\]
\[1-th^2\ α=\frac1{ch^2\ α}\]
\[1-cth^2\ α=\frac{-1}{sh^2\ α}\]
\[th\frac α2=\frac{ch\ α-1}{sh\ α}=\frac{sh\ α}{ch\ α+1}\]
\[cth\frac α2=\frac{sh\ α}{ch\ α-1}=\frac{ch\ α+1}{sh\ α}\]
\[ch\ α±ch\ ß=2·{}^{ch}_{sh}\frac{α+ß}2·{}^{ch}_{sh}\frac{α-ß}2\]
\[sh\ α±sh\ ß=2·sh\frac{α±ß}2·ch\frac{α∓ß}2\]
\[\displaystyle{th\ α±th\ ß=\frac{sh\left({α±ß}\right)}{ch\ α·ch\ ß}}\]
\[\displaystyle{cth\ α±cth\ ß=\frac{sh\left({ß±α}\right)}{sh\ ß·sh\ α}}\]
\[arch\ A=ln\left({A±\sqrt{A^2-1}}\right)\]
\[arsh\ A=ln\left({A±\sqrt{A^2+1}}\right)\]
\[arth\ A=\frac12·ln\frac{1+A}{1-A}\]
\[arcth\ A=\frac12·ln\frac{A+1}{A-1}\]
\[arth\ A+arcth\ A=ln\ i+ln\frac{A+1}{A-1}=ln\ i+ln\frac{1+A}{1-A}\]
\[±\left({arth\ A-arcth\ A}\right)=ln\ i\]
[Eop]
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